wtfpython/README.md

<h1 align="center"> What the f*ck Python? 🐍 </h1>
<p align="center"> A collection of interesting and tricky Python examples. </p>

[![WTFPL 2.0][license-image]][license-url]


Python, being awesome by design high-level and interpreter-based programming language, provides us with many features for the programmer's comfort. But sometimes, the outcomes of a Python snippet may not seem obvious to a regular user at first sight.

Here is a fun project attempting to collect such classic and tricky examples of unexpected behaviors in Python and discuss what exactly is happening under the hood!

While some of the examples you see below may not be WTFs in the truest sense, but they'll reveal some of the interesting parts of Python that you might be unaware of. I find it a nice way to learn the internals of a programming language, and I think you'll find them interesting as well!

If you're an experienced Python programmer, you might be familiar with most of these examples, and I might be able to revive some sweet old memories of yours being bitten by these gotchas :sweat_smile:

So, here ya go...

# Table of Contents

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- [Structure of the Examples](#structure-of-the-examples)
- [Usage](#usage)
- [👀 Examples](#-examples)
    - [Skipping lines?](#skipping-lines)
      - [💡 Explanation](#-explanation)
    - [Well, something is fishy...](#well-something-is-fishy)
      - [💡 Explanation](#-explanation-1)
    - [Time for some hash brownies!](#time-for-some-hash-brownies)
      - [💡 Explanation](#-explanation-2)
    - [Evaluation time discrepancy](#evaluation-time-discrepancy)
      - [💡 Explanation](#-explanation-3)
    - [Modifying a dictionary while iterating over it](#modifying-a-dictionary-while-iterating-over-it)
      - [💡 Explanation:](#-explanation)
    - [Deleting a list item while iterating over it](#deleting-a-list-item-while-iterating-over-it)
      - [💡 Explanation:](#-explanation-1)
    - [Backslashes at the end of string](#backslashes-at-the-end-of-string)
      - [💡 Explanation](#-explanation-4)
    - [Let's make a giant string!](#lets-make-a-giant-string)
      - [💡 Explanation](#-explanation-5)
    - [String interning](#string-interning)
      - [💡 Explanation:](#-explanation-2)
    - [Yes, it exists!](#yes-it-exists)
      - [💡 Explanation:](#-explanation-3)
    - [`is` is not what it is!](#is-is-not-what-it-is)
      - [💡 Explanation:](#-explanation-4)
    - [`is not ...` is not `is (not ...)`](#is-not--is-not-is-not-)
      - [💡 Explanation](#-explanation-6)
    - [The function inside loop sticks to the same output](#the-function-inside-loop-sticks-to-the-same-output)
      - [💡 Explanation](#-explanation-7)
    - [Loop variables leaking out of local scope!](#loop-variables-leaking-out-of-local-scope)
      - [💡 Explanation:](#-explanation-5)
    - [A tic-tac-toe where X wins in the first attempt!](#a-tic-tac-toe-where-x-wins-in-the-first-attempt)
      - [💡 Explanation:](#-explanation-6)
    - [Beware of default mutable arguments!](#beware-of-default-mutable-arguments)
      - [💡 Explanation:](#-explanation-7)
    - [Same operands, different story!](#same-operands-different-story)
      - [💡 Explanation:](#-explanation-8)
    - [Mutating the immutable!](#mutating-the-immutable)
      - [💡 Explanation:](#-explanation-9)
    - [Using a variable not defined in scope](#using-a-variable-not-defined-in-scope)
      - [💡 Explanation:](#-explanation-10)
    - [The disappearing variable from outer scope](#the-disappearing-variable-from-outer-scope)
      - [💡 Explanation:](#-explanation-11)
    - [Return return everywhere!](#return-return-everywhere)
      - [💡 Explanation:](#-explanation-12)
    - [When True is actually False](#when-true-is-actually-false)
      - [💡 Explanation:](#-explanation-13)
    - [Be careful with chained operations](#be-careful-with-chained-operations)
      - [💡 Explanation:](#-explanation-14)
    - [Name resolution ignoring class scope](#name-resolution-ignoring-class-scope)
      - [💡 Explanation](#-explanation-8)
    - [From filled to None in one instruction...](#from-filled-to-none-in-one-instruction)
      - [💡 Explanation](#-explanation-9)
    - [Explicit typecast of strings](#explicit-typecast-of-strings)
      - [💡 Explanation:](#-explanation-15)
    - [Class attributes and instance attributes](#class-attributes-and-instance-attributes)
      - [💡 Explanation:](#-explanation-16)
    - [Catching the Exceptions!](#catching-the-exceptions)
      - [💡 Explanation](#-explanation-10)
    - [Midnight time doesn't exist?](#midnight-time-doesnt-exist)
      - [💡 Explanation:](#-explanation-17)
    - [What's wrong with booleans?](#whats-wrong-with-booleans)
      - [💡 Explanation:](#-explanation-18)
    - [Needle in a Haystack](#needle-in-a-haystack)
      - [💡 Explanation:](#-explanation-19)
    - [The surprising comma](#the-surprising-comma)
      - [💡 Explanation:](#-explanation-20)
    - [For what?](#for-what)
      - [💡 Explanation:](#-explanation-21)
    - [not knot!](#not-knot)
      - [💡 Explanation:](#-explanation-22)
    - [Let's see if you can guess this?](#lets-see-if-you-can-guess-this)
      - [💡 Explanation:](#-explanation-23)
    - [Minor Ones](#minor-ones)
- [TODO: Hell of an example!](#todo-hell-of-an-example)
- [Contributing](#contributing)
- [Acknowledgements](#acknowledgements)
      - [Some nice Links!](#some-nice-links)
- [🎓 License](#-license)

<!-- END doctoc generated TOC please keep comment here to allow auto update -->

# Structure of the Examples

**Note:** All the examples mentioned below are tested on Python 3.5.2 interactive interpreter, and they should work for all the Python versions unless explicitly specified in the example description.

All the examples are structured like below:

> ### Some fancy Title
> 
> ```py
> # Setting up the code.
> # Preparation for the magic...
> ```
> 
> **Output (Python version):**
> ```py
> >>> triggering_statement
> Probably unexpected output
> ```
> (Optional): One line describing the unexpected output.
> 
> 
> #### 💡 Explanation:
> 
> * Brief explanation of what's happening and why is it happening.
>   ```py
>   Setting up examples for clarification (if necessary)
>   ```
>   **Output:**
>   ```py
>   >>> trigger # some example that makes it easy to unveil the magic
>   # some justified output
>   ```


# Usage

A good way to get the most out of these examples, in my opinion, will be just to read the examples chronologically, and for every example:
- Carefully read the initial code for setting up the example. If you're an experienced Python programmer, most of the times you will successfully anticipate what's gonna happen next.
- Read the output snippets and
  + Check if the outputs are the same as you'd expect.
  + Make sure know the exact reason behind the output being the way it is.
    - If no, read the explanation (and if you still don't understand, shout out! and create an issue [here](https://github.com/satwikkansal/wtfPython)).
    - If yes, give a gentle pat on your back, and you may skip to the next example.

PS: You can also read these examples at the command line. First install the npm package `wtfpython`,
```sh
$ npm install -g wtfpython
```
Now, just run `wtfpython` at the command line which will open this collection in your selected `$PAGER`.

#TODO: Add pypi package for reading via command line

# 👀 Examples

###  Skipping lines?

**Output:**
```py
>>> value = 11
>>> valuе = 32
>>> value
11
```

Wut?

**Note:** The easiest way to reproduce this is to simply copy the statements from the above snippet and paste them into your file/shell.

#### 💡 Explanation

Some non-Western characters look identical to letters in the English alphabet, but are considered distinct by the interpreter.

```py
>>> ord('е') # cyrillic 'e' (Ye)
1077
>>> ord('e') # latin 'e', as used in English and typed using standard keyboard
101
>>> 'е' == 'e'
False

>>> value = 42 # latin e
>>> valuе = 23 # cyrillic 'e', Python 2.x interpreter would raise a `SyntaxError` here
>>> value
42
```

The built-in `ord()` function returns a character's Unicode [code point](https://en.wikipedia.org/wiki/Code_point), and different code positions of cyrillic 'e' and latin 'e' justify the behavior of the above example.

---

###  Well, something is fishy...

```py
def square(x):
    """
    A simple function to calculate square of a number by addition.
    """
    sum_so_far = 0
    for counter in range(x):
        sum_so_far = sum_so_far + x
  return sum_so_far
```

**Output (Python 2.x):**

```py
>>> square(10)
10
```

Shouldn't that be 100?

**Note:** If you're not able to reproduce this, try running the file [mixed_tabs_and_spaces.py](/mixed_tabs_and_spaces.py) via the shell.

#### 💡 Explanation

* **Don't mix tabs and spaces!** The character just preceding return is a "tab",  and the code is indented by multiple of "4 spaces" elsewhere in the example.
* This is how Python handles tabs:
  > First, tabs are replaced (from left to right) by one to eight spaces such that the total number of characters up to and including the replacement is a multiple of eight <...>
* So the "tab" at the last line of `square` function is replaced with eight spaces, and it gets into the loop.
* Python 3 is nice enough to automatically throw an error for such cases.
    
    **Output (Python 3.x):**
    ```py
    TabError: inconsistent use of tabs and spaces in indentation
    ```

---

###  Time for some hash brownies!

1\.
```py
some_dict = {}
some_dict[5.5] = "Ruby"
some_dict[5.0] = "JavaScript"
some_dict[5] = "Python"
```

**Output:**
```py
>>> some_dict[5.5]
"Ruby"
>>> some_dict[5.0]
"Python"
>>> some_dict[5]
"Python"
```

"Python" destroyed the existence of "JavaScript"?

#### 💡 Explanation

* Python dictionaries check for equality and compare the hash value to determine if two keys are the same.
* Immutable objects with same value always have a same hash in Python.
  ```py
  >>> 5 == 5.0
  True
  >>> hash(5) == hash(5.0)
  True
  ```
  **Note:** Objects with different values may also have same hash (known as hash collision).
* When the statement `some_dict[5] = "Python"` is executed, the existing value "JavaScript" is overwritten with "Python" because Python recongnizes `5` and `5.0` as the same keys of the dictionary `some_dict`.
* This StackOverflow [answer](https://stackoverflow.com/a/32211042/4354153) explains beautifully the rationale behind it.

---

###  Evaluation time discrepancy

```py
array = [1, 8, 15]
g = (x for x in array if array.count(x) > 0)
array = [2, 8, 22]
```

**Output:**
```py
>>> print(list(g))
[8]
```

#### 💡 Explanation

- In a [generator](https://wiki.python.org/moin/Generators) expression, the `in` clause is evaluated at declaration time, but the conditional clause is evaluated at run time.
- So before run time, `array` is re-assigned to the list `[2, 8, 22]`, and since out of `1`, `8` and `15`, only the count of `8` is greater than `0`, the generator only yields `8`.

---

###  Modifying a dictionary while iterating over it

```py
x = {0: None}

for i in x:
    del x[i]
    x[i+1] = None
    print(i)
```

**Output:**

```
0
1
2
3
4
5
6
7
```

Yes, it runs for exactly **eight** times and stops.

#### 💡 Explanation:

* Iteration over a dictionary that you edit at the same time is not supported.
* It runs eight times because that's the point at which the dictionary resizes to hold more keys (we have eight deletion entries, so a resize is needed). This is actually an implementation detail.
* Refer to this StackOverflow [thread](https://stackoverflow.com/questions/44763802/bug-in-python-dict) explaining a similar example.

---

###  Deleting a list item while iterating over it

```py
list_1 = [1, 2, 3, 4]
list_2 = [1, 2, 3, 4]
list_3 = [1, 2, 3, 4]
list_4 = [1, 2, 3, 4]

for idx, item in enumerate(list_1):
    del item

for idx, item in enumerate(list_2):
    list_2.remove(item)

for idx, item in enumerate(list_3[:]):
    list_3.remove(item)

for idx, item in enumerate(list_4):
    list_4.pop(idx)
```

**Output:**
```py
>>> list_1
[1, 2, 3, 4]
>>> list_2
[2, 4]
>>> list_3
[]
>>> list_4
[2, 4]
```

Can you guess why the output is `[2, 4]`?

#### 💡 Explanation:

* It's never a good idea to change the object you're iterating over. The correct way to do so is to iterate over a copy of the object instead, and `list_3[:]` does just that.

     ```py
     >>> some_list = [1, 2, 3, 4]
     >>> id(some_list)
     139798789457608
     >>> id(some_list[:]) # Notice that python creates new object for sliced list.
     139798779601192
     ```


**Difference between `del`, `remove`, and `pop`:**
* `del var_name` just removes the binding of the `var_name` from the local or global namespace (That's why the `list_1` is unaffected).
* `remove` removes the first matching value, not a specific index, raises `ValueError` if the value is not found.
* `pop` removes element at a specific index and returns it, raises `IndexError` if an invalid index is specified.

**Why the output is `[2, 4]`?**
- The list iteration is done index by index, and when we remove `1` from `list_2` or `list_4`, the contents of the lists are now `[2, 3, 4]`. The remaining elements are shifted down, i.e. `2` is at index 0, and `3` is at index 1. Since the next iteration is going to look at index 1 (which is the `3`), the `2` gets skipped entirely. A similar thing will happen with every alternate element in the list sequence.

* Refer to this StackOverflow [thread](https://stackoverflow.com/questions/45946228/what-happens-when-you-try-to-delete-a-list-element-while-iterating-over-it) explaining the example
* See also this nice StackOverflow [thread](https://stackoverflow.com/questions/45877614/how-to-change-all-the-dictionary-keys-in-a-for-loop-with-d-items) for a similar example related to dictionaries in Python.

---

###  Backslashes at the end of string

**Output:**
```
>>> print("\\ some string \\")
>>> print(r"\ some string")
>>> print(r"\ some string \")

    File "<stdin>", line 1
      print(r"\ some string \")
                             ^
SyntaxError: EOL while scanning string literal
```

#### 💡 Explanation

- In a raw string literal, as indicated by the prefix `r`, the backslash doesn't have the special meaning.
- What the interpreter actually does, though, is simply change the behavior of backslashes, so they pass themselves and the following character through. That's why backslashes don't work at the end of a raw string.

---

###  Let's make a giant string!

This is not a WTF at all, just some nice things to be aware of :)

```py
def add_string_with_plus(iters):
    s = ""
    for i in range(iters):
        s += "xyz"
    assert len(s) == 3*iters

def add_string_with_format(iters):
    fs = "{}"*iters
    s = fs.format(*(["xyz"]*iters))
    assert len(s) == 3*iters

def add_string_with_join(iters):
    l = []
    for i in range(iters):
        l.append("xyz")
    s = "".join(l)
    assert len(s) == 3*iters

def convert_list_to_string(l, iters):
    s = "".join(l)
    assert len(s) == 3*iters
```

**Output:**
```py
>>> timeit(add_string_with_plus(10000))
100 loops, best of 3: 9.73 ms per loop
>>> timeit(add_string_with_format(10000))
100 loops, best of 3: 5.47 ms per loop
>>> timeit(add_string_with_join(10000))
100 loops, best of 3: 10.1 ms per loop
>>> l = ["xyz"]*10000
>>> timeit(convert_list_to_string(l, 10000))
10000 loops, best of 3: 75.3 µs per loop
```

#### 💡 Explanation
- You can read more about [timeit](https://docs.python.org/3/library/timeit.html) from here. It is generally used to measure the execution time of snippets.
- Don't use `+` for generating long strings — In Python, `str` is immutable, so the left and right strings have to be copied into the new string for every pair of concatenations. If you concatenate four strings of length 10, you'll be copying (10+10) + ((10+10)+10) + (((10+10)+10)+10) = 90 characters instead of just 40 characters. Things get quadratically worse as the number and size of the string increases.
- Therefore, it's advised to use `.format.` or `%` syntax (however, they are slightly slower than `+` for short strings).
- Or better, if already you've contents available in the form of an iterable object, then use `''.join(iterable_object)` which is much faster.

---

### String interning

```py
>>> a = "some_string"
>>> id(a)
140420665652016
>>> id("some" + "_" + "string") # Notice that both the ids are same.
140420665652016
# using "+", three strings:
>>> timeit.timeit("s1 = s1 + s2 + s3", setup="s1 = ' ' * 100000; s2 = ' ' * 100000; s3 = ' ' * 100000", number=100)
0.25748300552368164
# using "+=", three strings:
>>> timeit.timeit("s1 += s2 + s3", setup="s1 = ' ' * 100000; s2 = ' ' * 100000; s3 = ' ' * 100000", number=100)
0.012188911437988281
```

#### 💡 Explanation:
+ `+=` is faster than `+` for concatenating more than two strings because the first string (example, `s1` for `s1 += s2 + s3`) is not destroyed while calculating the complete string.
+ Both the strings refer to the same object because of CPython optimization that tries to use existing immutable objects in some cases (implementation specific) rather than creating a new object every time. You can read more about this [here](https://stackoverflow.com/questions/24245324/about-the-changing-id-of-an-immutable-string).

---

### Yes, it exists!

**The `else` clause for loops.** One typical example might be:

```py
  def does_exists_num(l, to_find):
      for num in l:
          if num == to_find:
              print("Exists!")
              break
      else:
          print("Does not exist")
```

**Output:**
```py
>>> some_list = [1, 2, 3, 4, 5]
>>> does_exists_num(some_list, 4)
Exists!
>>> does_exists_num(some_list, -1)
Does not exist
```

**The `else` clause in exception handling.** An example,

```py
try:
    pass
except:
    print("Exception occurred!!!")
else:
    print("Try block executed successfully...")
```

**Output:**
```py
Try block executed successfully...
```

#### 💡 Explanation:
- The `else` clause after a loop is executed only when there's no explicit `break` after all the iterations.
- `else` clause after try block is also called "completion clause" as reaching the `else` clause in a `try` statement means that the try block actually completed successfully.

---

###  `is` is not what it is!

The following is a very famous example present all over the internet.

```py
>>> a = 256
>>> b = 256
>>> a is b
True

>>> a = 257
>>> b = 257
>>> a is b
False

>>> a = 257; b = 257
>>> a is b
True
```


#### 💡 Explanation:

**The difference between `is` and `==`**

* `is` operator checks if both the operands refer to the same object (i.e. it checks if the identity of the operands matches or not).
* `==` operator compares the values of both the operands and checks if they are the same.
* So `is` is for reference equality and `==` is for value equality. An example to clear things up,
  ```py
  >>> [] == []
  True
  >>> [] is [] # These are two empty lists at two different memory locations.
  False
  ```

**`256` is an existing object but `257` isn't**

When you start up python the numbers from `-5` to `256` will be allocated. These numbers are used a lot, so it makes sense just to have them ready.

Quoting from https://docs.python.org/3/c-api/long.html
> The current implementation keeps an array of integer objects for all integers between -5 and 256, when you create an int in that range you just get back a reference to the existing object. So it should be possible to change the value of 1. I suspect the behavior of Python, in this case, is undefined. :-)

```py
>>> id(256)
10922528
>>> a = 256
>>> b = 256
>>> id(a)
10922528
>>> id(b)
10922528
>>> id(257)
140084850247312
>>> x = 257
>>> y = 257
>>> id(x)
140084850247440
>>> id(y)
140084850247344
```

Here the interpreter isn't smart enough while executing `y = 257` to recognize that we've already created an integer of the value `257` and so it goes on to create another object in the memory.


**Both `a` and `b` refer to the same object, when initialized with same value in the same line.**

```py
>>> a, b = 257, 257
>>> id(a)
140640774013296
>>> id(b)
140640774013296
>>> a = 257
>>> b = 257
>>> id(a)
140640774013392
>>> id(b)
140640774013488
```


* When a and b are set to `257` in the same line, the Python interpreter creates a new object, then references the second variable at the same time. If you do it on separate lines, it doesn't "know" that there's already `257` as an object.
* It's a compiler optimization and specifically applies to the interactive environment. When you enter two lines in a live interpreter, they're compiled separately, therefore optimized separately. If you were to try this example in a `.py` file, you would not see the same behavior, because the file is compiled all at once.

---

###  `is not ...` is not `is (not ...)`

```py
>>> 'something' is not None
True
>>> 'something' is (not None)
False
```

#### 💡 Explanation

- `is not` is a single binary operator, and has behavior different than using `is` and `not` separated.
- `is not` evaluates to `False` if the variables on either side of the operator point to the same object and `True` otherwise.

---

###  The function inside loop sticks to the same output

```py
funcs = []
results = []
for x in range(7):
    def some_func():
        return x
    funcs.append(some_func)
    results.append(some_func())

funcs_results = [func() for func in funcs]
```

**Output:**
```py
>>> results
[0, 1, 2, 3, 4, 5, 6]
>>> funcs_results
[6, 6, 6, 6, 6, 6, 6]
```
Even when the values of `x` were different in every iteration prior to appending `some_func` to `funcs`, all the functions return 6.

//OR

```py
>>> powers_of_x = [lambda x: x**i for i in range(10)]
>>> [f(2) for f in powers_of_x]
[512, 512, 512, 512, 512, 512, 512, 512, 512, 512]
```

#### 💡 Explanation

- When defining a function inside a loop that uses the loop variable in its body, the loop function's closure is bound to the variable, not its value. So all of the functions use the latest value assigned to the variable for computation.

- To get the desired behavior you can pass in the loop variable as a named variable to the function. **Why this works?** Because this will define the variable again within the function's scope.

    ```py
    funcs = []
    for x in range(7):
        def some_func(x=x):
            return x
        funcs.append(some_func)
    ```

    **Output:**
    ```py
    >>> funcs_results = [func() for func in funcs]
    >>> funcs_results
    [0, 1, 2, 3, 4, 5, 6]
    ```


---

###  Loop variables leaking out of local scope!

1\.
```py
for x in range(7):
    if x == 6:
        print(x, ': for x inside loop')
print(x, ': x in global')
```

**Output:**
```py
6 : for x inside loop
6 : x in global
```

But `x` was never defined outside the scope of for loop...

2\.
```py
# This time let's initialize x first
x = -1
for x in range(7):
    if x == 6:
        print(x, ': for x inside loop')
print(x, ': x in global')
```

**Output:**
```py
6 : for x inside loop
6 : x in global
```

3\.
```
x = 1
print([x for x in range(5)])
print(x, ': x in global')
```

**Output (on Python 2.x):**
```
[0, 1, 2, 3, 4]
(4, ': x in global')
```

**Output (on Python 3.x):**
```
[0, 1, 2, 3, 4]
1 : x in global
```

#### 💡 Explanation:

- In Python, for-loops use the scope they exist in and leave their defined loop-variable behind. This also applies if we explicitly defined the for-loop variable in the global namespace before. In this case, it will rebind the existing variable.

- The differences in the output of Python 2.x and Python 3.x interpreters for list comprehension example can be explained by following change documented in [What’s New In Python 3.0](https://docs.python.org/3/whatsnew/3.0.html) documentation:

    > "List comprehensions no longer support the syntactic form `[... for var in item1, item2, ...]`. Use `[... for var in (item1, item2, ...)]` instead. Also, note that list comprehensions have different semantics: they are closer to syntactic sugar for a generator expression inside a `list()` constructor, and in particular the loop control variables are no longer leaked into the surrounding scope."


---

###  A tic-tac-toe where X wins in the first attempt!

```py
# Let's initialize a row
row = [""]*3 #row i['', '', '']
# Let's make a board
board = [row]*3
```

**Output:**
```py
>>> board
[['', '', ''], ['', '', ''], ['', '', '']]
>>> board[0]
['', '', '']
>>> board[0][0]
''
>>> board[0][0] = "X"
>>> board
[['X', '', ''], ['X', '', ''], ['X', '', '']]
```

We didn't assigned 3 "X"s or did we?

#### 💡 Explanation:

When we initialize `row` variable, this visualization explains what happens in the memory

![image](/images/tic-tac-toe/after_row_initialized.png)

And when the `board` is initialized by multiplying the `row`, this is what happens inside the memory (each of the elements `board[0]`, `board[1]` and `board[2]` is a reference to the same list referred by `row`)

![image](/images/tic-tac-toe/after_board_initialized.png)

---

###  Beware of default mutable arguments!

```py
def some_func(default_arg=[]):
    default_arg.append("some_string")
    return default_arg
```

**Output:**
```py
>>> some_func()
['some_string']
>>> some_func()
['some_string', 'some_string']
>>> some_func([])
['some_string']
>>> some_func()
['some_string', 'some_string', 'some_string']
```

#### 💡 Explanation:

- The default mutable arguments of functions in Python aren't really initialized every time you call the function. Instead, the recently assigned value to them is used as the default value. When we explicitly passed `[]` to `some_func` as the argument, the default value of the `default_arg` variable was not used, so the function returned as expected.

    ```py
    def some_func(default_arg=[]):
        default_arg.append("some_string")
        return default_arg
    ```

    **Output:**
    ```py
    >>> some_func.__defaults__ #This will show the default argument values for the function
    ([],)
    >>> some_func()
    >>> some_func.__defaults__
    (['some_string'],)
    >>> some_func()
    >>> some_func.__defaults__
    (['some_string', 'some_string'],)
    >>> some_func([])
    >>> some_func.__defaults__
    (['some_string', 'some_string'],)
    ```

- A common practice to avoid bugs due to mutable arguments is to assign `None` as the default value and later check if any value is passed to the function corresponding to that argument. Example:

    ```py
    def some_func(default_arg=None):
        if not default_arg:
            default_arg = []
        default_arg.append("some_string")
        return default_arg
    ```

---

### Same operands, different story!

1\.
```py
a = [1, 2, 3, 4]
b = a
a = a + [5, 6, 7, 8]
```

**Output:**
```py
>>> a
[1, 2, 3, 4, 5, 6, 7, 8]
>>> b
[1, 2, 3, 4]
```

2\.
```py
a = [1, 2, 3, 4]
b = a
a += [5, 6, 7, 8]
```

**Output:**
```py
>>> a
[1, 2, 3, 4, 5, 6, 7, 8]
>>> b
[1, 2, 3, 4, 5, 6, 7, 8]
```

#### 💡 Explanation:

*  `a += b` doesn't always behave the same way as `a = a + b`.  Classes *may* implement the *`op=`* operators differently, and lists do this.

* The expression `a = a + [5,6,7,8]` generates a new list and sets `a`'s reference to that new list, leaving `b` unchanged.

* The expression `a + =[5,6,7,8]` is actually mapped to an "extend" function that operates on the list such that `a` and `b` still point to the same list that has been modified in-place.

---

###  Mutating the immutable!

```py
some_tuple = ("A", "tuple", "with", "values")
another_tuple = ([1, 2], [3, 4], [5, 6])
```

**Output:**
```py
>>> some_tuple[2] = "change this"
TypeError: 'tuple' object does not support item assignment
>>> another_tuple[2].append(1000) #This throws no error
>>> another_tuple
([1, 2], [3, 4], [5, 6, 1000])
>>> another_tuple[2] += [99, 999]
TypeError: 'tuple' object does not support item assignment
>>> another_tuple
([1, 2], [3, 4], [5, 6, 1000, 99, 999])
```

But I thought tuples were immutable...

#### 💡 Explanation:

* Quoting from https://docs.python.org/2/reference/datamodel.html

    > Immutable sequences
        An object of an immutable sequence type cannot change once it is created. (If the object contains references to other objects, these other objects may be mutable and may be modified; however, the collection of objects directly referenced by an immutable object cannot change.)

* `+=` operator changes the list in-place. The item assignment doesn't work, but when the exception occurs, the item has already been changed in place.

---

###  Using a variable not defined in scope

```py
a = 1
def some_func():
    return a

def another_func():
    a += 1
    return a
```

**Output:**
```py
>>> some_func()
1
>>> another_func()
UnboundLocalError: local variable 'a' referenced before assignment
```

#### 💡 Explanation:
* When you make an assignment to a variable in a scope, it becomes local to that scope. So `a` becomes local to the scope of `another_func`,  but it has not been initialized previously in the same scope which throws an error.
* Read [this](http://sebastianraschka.com/Articles/2014_python_scope_and_namespaces.html) short but an awesome guide to learn more about how namespaces and scope resolution works in Python.
* To modify the outer scope variable `a` in `another_func`, use `global` keyword.
  ```py
  def another_func()
      global a
      a += 1
      return a
  ```
  
  **Output:**
  ```py
  >>> another_func()
  2
  ```

---

###  The disappearing variable from outer scope

```py
e = 7
try:
    raise Exception()
except Exception as e:
    pass
```

**Output (Python 2.x):**
```py
>>> print(e)
# prints nothing
```

**Output (Python 3.x):**
```py
>>> print(e)
NameError: name 'e' is not defined
```

#### 💡 Explanation:

* Source: https://docs.python.org/3/reference/compound_stmts.html#except

  When an exception has been assigned using `as` target, it is cleared at the end of the except clause. This is as if

  ```py
  except E as N:
      foo
  ```

  was translated to

  ```py
  except E as N:
      try:
          foo
      finally:
          del N
  ```

  This means the exception must be assigned to a different name to be able to refer to it after the except clause. Exceptions are cleared because, with the traceback attached to them, they form a reference cycle with the stack frame, keeping all locals in that frame alive until the next garbage collection occurs.

* The clauses are not scoped in Python. Everything in the example is present in the same scope, and the variable `e` got removed due to the execution of the `except` clause. The same is not the case with functions which have their separate inner-scopes. The example below illustrates this:

     ```py
     def f(x):
         del(x)
         print(x)

     x = 5
     y = [5, 4, 3]
     ```

     **Output:**
     ```py
     >>>f(x)
     UnboundLocalError: local variable 'x' referenced before assignment
     >>>f(y)
     UnboundLocalError: local variable 'x' referenced before assignment
     >>> x
     5
     >>> y
     [5, 4, 3]
     ```

* In Python 2.x the variable name `e` gets assigned to `Exception()` instance, so when you try to print, it prints nothing.

    **Output (Python 2.x):**
    ```py
    >>> e
    Exception()
    >>> print e
    # Nothing is printed!
    ```


---

###  Return return everywhere!

```py
def some_func():
    try:
        return 'from_try'
    finally:
        return 'from_finally'
```

**Output:**
```py
>>> some_func()
'from_finally'
```

#### 💡 Explanation:

- When a `return`, `break` or `continue` statement is executed in the `try` suite of a "try…finally" statement, the `finally` clause is also executed ‘on the way out.
- The return value of a function is determined by the last `return` statement executed. Since the `finally` clause always executes, a `return` statement executed in the `finally` clause will always be the last one executed.

---

###  When True is actually False

```py
True = False
if True == False:
    print("I've lost faith in truth!")
```

**Output:**
```
I've lost faith in truth!
```

#### 💡 Explanation:

- Initially, Python used to have no `bool` type (people used 0 for false and non-zero value like 1 for true). Then they added `True`, `False`, and a `bool` type, but, for backward compatibility, they couldn't make `True` and `False` constants- they just were built-in variables.
- Python 3 was backwards-incompatible, so it was now finally possible to fix that, and so this example won't work with Python 3.x!

---

###  Be careful with chained operations

```py
>>> True is False == False
False
>>> False is False is False
True
>>> 1 > 0 < 1
True
>>> (1 > 0) < 1
False
>>> 1 > (0 < 1)
False
```

#### 💡 Explanation:

As per https://docs.python.org/2/reference/expressions.html#not-in

> Formally, if a, b, c, ..., y, z are expressions and op1, op2, ..., opN are comparison operators, then a op1 b op2 c ... y opN z is equivalent to a op1 b and b op2 c and ... y opN z, except that each expression is evaluated at most once.

While such behavior might seem silly to you in the above examples, it's fantastic with stuff like `a == b == c` and `0 <= x <= 100`.

* `False is False is False` is equivalent to `(False is False) and (False is False)`
* `True is False == False` is equivalent to `True is False and False == False` and since the first part of the statement (`True is False`) evaluates to `False`, the overall expression evaluates to `False`.
* `1 > 0 < 1` is equivalent to `1 > 0 and 0 < 1` which evaluates to `True`.
* The expression `(1 > 0) < 1` is equivalent to `True < 1` and
  ```py
  >>> int(True)
  1
  >>> True + 1 #not relevant for this example, but just for fun
  2
  ```
  So, `1 < 1` evaluates to `False`


---

###  Name resolution ignoring class scope

1\.
```py
x = 5
class SomeClass:
    x = 17
    y = (x for i in range(10))
```

**Output:**
```py
>>> list(SomeClass.y)[0]
5
```

2\.
```py
x = 5
class SomeClass:
    x = 17
    y = [x for i in range(10)]
```

**Output (Python 2.x):**
```py
>>> SomeClass.y[0]
17
```

**Output (Python 3.x):**
```py
>>> SomeClass.y[0]
5
```

#### 💡 Explanation
- Scopes nested inside class definition ignore names bound at the class level.
- A generator expression has its own scope.
- Starting from Python 3.X, list comprehensions also have their own scope.

---
###  From filled to None in one instruction...

```py
some_list = [1, 2, 3]
some_dict = {
  "key_1": 1,
  "key_2": 2,
  "key_3": 3
}

some_list = some_list.append(4)
some_dict = some_dict.update({"key_4": 4})
```

**Output:**
```py
>>> print(some_list)
None
>>> print(some_dict)
None
```

#### 💡 Explanation

Most methods that modify the items of sequence/mapping objects like `list.append`, `dict.update`, `list.sort`, etc. modify the objects in-place and return `None`. The rationale behind this is to improve performance by avoiding making a copy of the object if the operation can be done in-place (Referred from [here](http://docs.python.org/2/faq/design.html#why-doesn-t-list-sort-return-the-sorted-list))

---

###  Explicit typecast of strings

This is not a WTF at all, but it took me so long to realize such things existed in Python. So sharing it here for the beginners.

```py
a = float('inf')
b = float('nan')
c = float('-iNf')  #These strings are case-insensitive
d = float('nan')
```

**Output:**
```py
>>> a
inf
>>> b
nan
>>> c
-inf
>>> float('some_other_string')
ValueError: could not convert string to float: some_other_string
>>> a == -c #inf==inf
True
>>> None == None # None==None
True
>>> b == d #but nan!=nan
False
>>> 50/a
0.0
>>> a/a
nan
>>> 23 + b
nan
```

#### 💡 Explanation:

`'inf'` and `'nan'` are special strings (case-insensitive), which when explicitly type casted to `float` type, are used to represent mathematical "infinity" and "not a number" respectively.

---

###  Class attributes and instance attributes

1\.
```py
class A:
    x = 1

class B(A):
    pass

class C(A):
    pass
```

**Ouptut:**
```py
>>> A.x, B.x, C.x
(1, 1, 1)
>>> B.x = 2
>>> A.x, B.x, C.x
(1, 2, 1)
>>> A.x = 3
>>> A.x, B.x, C.x
(3, 2, 3)
>>> a = A()
>>> a.x, A.x
(3, 3)
>>> a.x += 1
>>> a.x, A.x
(4, 3)
```

2\.
```py
class SomeClass:
    some_var = 15
    some_list = [5]
    another_list = [5]
    def __init__(self, x):
        self.some_var = x + 1
        self.some_list = self.some_list + [x]
        self.another_list += [x]
```

**Output:**

```py
>>> some_obj = SomeClass(420)
>>> some_obj.some_list
[5, 420]
>>> some_obj.another_list
[5, 420]
>>> another_obj = SomeClass(111)
>>> another_obj.some_list
[5, 111]
>>> another_obj.another_list
[5, 420, 111]
>>> another_obj.another_list is SomeClass.another_list
True
>>> another_obj.another_list is some_obj.another_list
True
```


#### 💡 Explanation:

* Class variables and variables in class instances are internally handled as dictionaries of a class object. If a variable name is not found in the dictionary of the current class, the parent classes are searched for it.
* The `+=` operator modifies the mutable object in-place without creating a new object. So changing the attribute of one instance affects the other instances and the class attribute as well.

---

###  Catching the Exceptions!

```py
some_list = [1, 2, 3]
try:
    # This should raise an ``IndexError``
    print(some_list[4])
except IndexError, ValueError:
    print("Caught!")

try:
    # This should raise a ``ValueError``
    some_list.remove(4)
except IndexError, ValueError:
    print("Caught again!")
```

**Output (Python 2.x):**
```py
Caught!

ValueError: list.remove(x): x not in list
```

**Output (Python 3.x):**
```py
  File "<input>", line 3
    except IndexError, ValueError:
                     ^
SyntaxError: invalid syntax
```

#### 💡 Explanation

* To add multiple Exceptions to the except clause, you need to pass them as parenthesized tuple as the first argument. The second argument is an optional name, which when supplied will bind the Exception instance that has been raised. Example,
  ```py
  some_list = [1, 2, 3]
  try:
     # This should raise a ``ValueError``
     some_list.remove(4)
  except (IndexError, ValueError), e:
     print("Caught again!")
     print(e)
  ```
  **Output (Python 2.x):**
  ```
  Caught again!
  list.remove(x): x not in list
  ```
  **Output (Python 3.x):**
  ```py
    File "<input>", line 4
      except (IndexError, ValueError), e:
                                       ^
  IndentationError: unindent does not match any outer indentation level
  ```

* Separating the exception from the variable with a comma is deprecated and does not work in Python 3; the correct way is to use `as`. Example,
  ```py
  some_list = [1, 2, 3]
  try:
      some_list.remove(4)

  except (IndexError, ValueError) as e:
      print("Caught again!")
      print(e)
  ```
  **Output:**
  ```
  Caught again!
  list.remove(x): x not in list
  ```

---

### Midnight time doesn't exist?

```py
from datetime import datetime

midnight = datetime(2018, 1, 1, 0, 0)
midnight_time = midnight.time()

noon = datetime(2018, 1, 1, 12, 0)
noon_time = noon.time()

if midnight_time:
    print("Time at midnight is", midnight_time)

if noon_time:
    print("Time at noon is", noon_time)
```

**Output:**
```sh
('Time at noon is', datetime.time(12, 0))
```
The midnight time is not printed.

#### 💡 Explanation:

Before Python 3.5, the boolean value for `datetime.time` object was considered to be `False` if it represented midnight in UTC. It is error-prone when using the `if obj:` syntax to check if the `obj` is null or some equivalent of "empty."

---

### What's wrong with booleans?

1\.
```py
# A simple example to count the number of boolean and
# integers in an iterable of mixed data types.
mixed_list = [False, 1.0, "some_string", 3, True, [], False]
integers_found_so_far = 0
booleans_found_so_far = 0

for item in mixed_list:
    if isinstance(item, int):
        integers_found_so_far += 1
    elif isinstance(item, bool):
        booleans_found_so_far += 1
```

**Outuput:**
```py
>>> booleans_found_so_far
0
>>> integers_found_so_far
4
```

2\.
```py
another_dict = {}
another_dict[True] = "JavaScript"
another_dict[1] = "Ruby"
another_dict[1.0] = "Python"
```

**Output:**
```py
>>> another_dict[True]
"Python"
```


#### 💡 Explanation:

* Booleans are a subclass of `int`
  ```py
  >>> isinstance(True, int)
  True
  >>> isinstance(False, int)
  True
  ```

* The integer value of `True` is `1` and that of `False` is `0`.
  ```py
  >>> True == 1 == 1.0 and False == 0 == 0.0
  True
  ```

* See this StackOverflow [answer](https://stackoverflow.com/a/8169049/4354153) for rationale behind it.

---

### Needle in a Haystack

Almost every Python programmer would have faced this situation.

```py
t = ('one', 'two')
for i in t:
    print(i)

t = ('one')
for i in t:
    print(i)

t = ()
print(t)
```

**Output:**
```py
one
two
o
n
e
tuple()
```


#### 💡 Explanation:
* The correct statement for expected behavior is `t = ('one',)` or `t = 'one',` (missing comma) otherwise the interpreter considers `t` to be a `str` and iterates over it character by character.
* `()` is a special token and denotes empty `tuple`.

---

### The surprising comma

Suggested by @MostAwesomeDude in [this](https://github.com/satwikkansal/wtfPython/issues/1) issue.

**Output:**
```py
>>> def f(x, y,):
...     print(x, y)
...
>>> def g(x=4, y=5,):
...     print(x, y)
...
>>> def h(x, **kwargs,):
  File "<stdin>", line 1
    def h(x, **kwargs,):
                     ^
SyntaxError: invalid syntax
>>> def h(*args,):
  File "<stdin>", line 1
    def h(*args,):
                ^
SyntaxError: invalid syntax
```

#### 💡 Explanation:

- Trailing comma is not always legal in formal parameters list of a Python function.
-  In Python, the argument list is defined partially with leading commas and partially with trailing commas. This conflict causes situations where a comma is trapped in the middle, and no rule accepts it.
-  **Note:** The trailing comma problem is [fixed in Python 3.6](https://bugs.python.org/issue9232). The remarks in [this](https://bugs.python.org/issue9232#msg248399) post discuss in brief different usages of trailing commas in Python.

---

### For what?

Suggested by @MittalAshok in [this](https://github.com/satwikkansal/wtfpython/issues/23) issue.

```py
some_string = "wtf"
some_dict = {}
for i, some_dict[i] in enumerate(some_string):
    pass
```

**Outuput:**
```py
>>> some_dict # An indexed dict is created.
{0: 'w', 1: 't', 2: 'f'}
```

####  💡 Explanation:

* A `for` statement is defined in the [Python grammar](https://docs.python.org/3/reference/grammar.html) as:
  ```
  for_stmt: 'for' exprlist 'in' testlist ':' suite ['else' ':' suite]
  ```
  Where `exprlist` is the assignment target. This means that the equivalent of `{exprlist} = {next_value}` is **executed for each item** in the iterable.
  An interesting example suggested by @tukkek in [this](https://github.com/satwikkansal/wtfPython/issues/11) issue illustrates this:
  ```py
  for i in range(4):
      print(i)
      i = 10
  ```

  **Output:**
  ```
  0
  1
  2
  3
  ```

  Did you expect the loop to run just once?

  **💡 Explanation:**

  - The assignment statement `i = 10` never affects the iterations of the loop because of the way for loops work in Python. Before the beginning of every iteration, the next item provided by the iterator (`range(4)` this case) is unpacked and assigned the target list variables (`i` in this case).

* The `enumerate(some_string)` function yields a new value `i` (A counter going up) and a character from the `some_string` in each iteration. It then sets the (just assigned) `i` key of the dictionary `some_dict` to that character. The unrolling of the loop can be simplified as:
  ```py
  >>> i, some_dict[i] = (0, 'w')
  >>> i, some_dict[i] = (1, 't')
  >>> i, some_dict[i] = (2, 'f')
  >>> some_dict
  ```

---

### not knot!

Suggested by @MostAwesomeDude in [this](https://github.com/satwikkansal/wtfPython/issues/1) issue.

```py
x = True
y = False
```

**Output:**
```py
>>> not x == y
True
>>> x == not y
  File "<input>", line 1
    x == not y
           ^
SyntaxError: invalid syntax
```

#### 💡 Explanation:

* Operator precedence affects how an expression is evaluated, and `==` operator has higher precedence than `not` operator in Python.
* So `not x == y` is equivalent to `not (x == y)` which is equivalent to `not (True == False)` finally evaluating to `True`.
* But `x == not y` raises a `SyntaxError` because it can be thought of being equivalent to `(x == not) y` and not `x == (not y)` which you might have expected at first sight.
* The parser expected the `not` token to be a part of the `not in` operator (because both `==` and `not in` operators have same precedence), but after not being able to find a `in` token following the `not` token, it raises a `SyntaxError`.

---

### Let's see if you can guess this?

Suggested by @PiaFraus in [this](https://github.com/satwikkansal/wtfPython/issues/9) issue.

```py
a, b = a[b] = {}, 5
```

**Output:**
```py
>>> a
{5: ({...}, 5)}
```

#### 💡 Explanation:

* According to [Python language reference](https://docs.python.org/2/reference/simple_stmts.html#assignment-statements), assignment statements have the form
  ```
  (target_list "=")+ (expression_list | yield_expression)
  ```
  and
  > An assignment statement evaluates the expression list (remember that this can be a single expression or a comma-separated list, the latter yielding a tuple) and assigns the single resulting object to each of the target lists, from left to right.

* The `+` in `(target_list "=")+` means there can be **one or more** target lists. In this case, target lists are `a, b` and `a[b]` (note the expression list is exactly one, which in our case is `{}, 5`).

* After the expression list is evaluated, it's value is unpacked to the target lists from **left to right**. So, in our case, first the `{}, 5` tuple is unpacked to `a, b` and we now have `a = {}` and `b = 5`.

* `a` is now assigned to `{}` which is a mutable object.

* The second target list is `a[b]` (you may expect this to throw an error because both `a` and `b` have not been defined in the statements before. But remember, we just assigned `a` to `{}` and `b` to `5`).

* Now, we are setting the key `5` in the dictionary to the tuple `({}, 5)` creating a circular reference (the `{...}` in the output refers to the same object that `a` is already referencing). Another simpler example of circular reference could be
  ```py
  >>> some_list = some_list[0] = [0]
  >>> some_list
  [[...]]
  >>> some_list[0]
  [[...]]
  >>> some_list is some_list[0]
  True
  ```
  Similar is the case in our example (`a[b][0]` is the same object as `a`)

* So to sum it up, you can break the example down to
  ```py
  a, b = {}, 5
  a[b] = a, b
  ```
  And the circular reference can be justified by the fact that `a[b][0]` is the same object as `a`
  ```py
  >>> a[b][0] is a
  True
  ```

---

###  Minor Ones

* `join()` is a string operation instead of list operation. (sort of counter-intuitive at first usage)
  
  **💡 Explanation:**
  If `join()` is a method on a string then it can operate on any iterable (list, tuple, iterators). If it were a method on a list, it'd have to be implemented separately by every type. Also, it doesn't make much sense to put a string-specific method on a generic `list` object API.

* Few weird looking but semantically correct statements:
  + `[] = ()` is a semantically correct statement (unpacking an empty `tuple` into an empty `list`)
  + `'a'[0][0][0][0][0]` is also a semantically correct statement as strings are [sequences](https://docs.python.org/3/glossary.html#term-sequence)(iterables supporting element access using integer indices) in Python.
  + `3 --0-- 5 == 8` and `--5 == 5` are both semantically correct statements and evaluate to `True`.

* Given that `a` is a number, `++a` and `--a` are both valid Python statements, but don't behave the same way as compared with similar statements in languages like C, C++ or Java.
  ```py
  >>> a = 5
  >>> a
  5
  >>> ++a
  5
  >>> --a
  5
  ```

  **💡 Explanation:**
  + There is no `++` operator in Python grammar. It is actually two `+` operators.
  + `++a` parses as `+(+a)` which translates to `a`. Similarly, the output of the statement `--a` can be justified.
  + This StackOverflow [thread](https://stackoverflow.com/questions/3654830/why-are-there-no-and-operators-in-python) discusses the rationale behind the absence of increment and decrement operators in Python.

* Python uses 2 bytes for local variable storage in functions. In theory, this means that only 65536 variables can be defined in a function. However, python has a handy solution built in that can be used to store more than 2^16 variable names. The following code demonstrates what happens in the stack when more than 65536 local variables are defined (Warning: This code prints around 2^18 lines of text, so be prepared!):
     ```py
     import dis
     exec("""
     def f():*     """ + """
         """.join(["X"+str(x)+"=" + str(x) for x in range(65539)]))

     f()

     print(dis.dis(f))
     ```

* Multiple Python threads won't run your *Python code* concurrently (yes you heard it right!). It may seem intuitive to spawn several threads and let them execute your Python code concurrently, but, because of the [Global Interpreter Lock](https://wiki.python.org/moin/GlobalInterpreterLock) in Python, all you're doing is making your threads execute on the same core turn by turn. Python threads are good for IO-bound tasks, but to achieve actual parallelization in Python for CPU-bound tasks, you might want to use the Python [multiprocessing](https://docs.python.org/2/library/multiprocessing.html) module.

* List slicing with out of the bounds indices throws no errors
  ```py
  >>> some_list = [1, 2, 3, 4, 5]
  >>> some_list[111:]
  []
  ```

---


# TODO: Hell of an example!

Trying to come up with an example that combines multiple examples discussed above, making it difficult for the reader to guess the output correctly :sweat_smile:.

# Contributing

All patches are Welcome! Filing an [issue](https://github.com/satwikkansal/wtfpython/issues/new) first before submitting a patch will be appreciated :) Please see [CONTRIBUTING.md](/CONTRIBUTING.md) for further details.

For discussions, either create a new [issue](https://github.com/satwikkansal/wtfpython/issues/new) or ping on the Gitter [channel](https://gitter.im/wtfpython/Lobby)

# Acknowledgements

The idea and design for this collection are inspired by Denys Dovhan's awesome project [wtfjs](https://github.com/denysdovhan/wtfjs).

#### Some nice Links!
* https://www.youtube.com/watch?v=sH4XF6pKKmk
* https://www.reddit.com/r/Python/comments/3cu6ej/what_are_some_wtf_things_about_python
* https://sopython.com/wiki/Common_Gotchas_In_Python
* https://stackoverflow.com/questions/530530/python-2-x-gotchas-and-landmines
* https://stackoverflow.com/questions/1011431/common-pitfalls-in-python (This StackOverflow thread has some DOs and DONTs which are worth reading.)

# 🎓 License

[![CC 4.0][license-image]][license-url]

&copy; [Satwik Kansal](https://satwikkansal.xyz)

[license-url]: http://www.wtfpl.net
[license-image]: https://img.shields.io/badge/License-WTFPL%202.0-lightgrey.svg?style=flat-square