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Correct ambiguous statement

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* Removes the statement "So if the is operator returns True
then the equality is definitely True" because it contradicts
in case of float('nan')
* Adds a small example with explaination for the same.
This commit is contained in:
Satwik Kansal 2017-09-01 13:43:44 +05:30
parent d91404dc69
commit 8e69c66246
1 changed files with 8 additions and 3 deletions
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README.md vendored
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@ -521,8 +521,13 @@ True
* `is` operator checks if both the operands refer to the same object (i.e. it checks if the identity of the operands matches or not).
* `==` operator compares the values of both the operands and checks if they are the same.
* So if the `is` operator returns `True` then the equality is definitely `True`, but the opposite may or may not be True.
* So `is` is for reference equality and `==` is for value equality. An example to clear things up,
```py
>>> [] == []
True
>>> [] is [] # These are two empty lists at two different memory locations.
False
```
**`256` is an existing object but `257` isn't**
@ -550,7 +555,7 @@ Quoting from https://docs.python.org/3/c-api/long.html
140084850247344
```
Here the interpreter isn't smart enough while executing `y = 257` to recognize that we've already created an integer of the value `257 ,` and so it goes on to create another object in the memory.
Here the interpreter isn't smart enough while executing `y = 257` to recognize that we've already created an integer of the value `257` and so it goes on to create another object in the memory.
**Both `a` and `b` refer to the same object, when initialized with same value in the same line.**