fix wLangId in ccid-driver.c

This is not a part of pin pad support series of mine.

As I found the bug while I am preparing the patches, I report this.

As CCID protocol is little endian, wLangId of US English = 0x0409
is represented as two bytes of 0x09 then 0x04.

It is really confusing that the code like following is floating
around:
	pin_verify -> wLangId = HOST_TO_CCID_16(0x0904);

But, it is 0x0409 (not 0x0904).  It is defined in the documentation:

    http://www.usb.org/developers/docs/USB_LANGIDs.pdf

and origin of this table is Microsoft.  We can see it at:

    http://msdn.microsoft.com/en-us/library/bb165625%28VS.80%29.aspx

Yes, it would be better not to hard-code 0x0409.  It would be better
to try current locale of the user, or to use the first entry of string
descriptor.  I don't have time to implement such a thing...

scd/ccid-driver.c

@@ -3136,8 +3136,8 @@ ccid_transceive_secure (ccid_driver_t handle,
   if (pinlen_min && pinlen_max && pinlen_min == pinlen_max)
     msg[17] |= 0x01; /* Max size reached.  */
   msg[18] = 0xff; /* bNumberMessage: Default. */
-  msg[19] = 0x04; /* wLangId-High. */
-  msg[20] = 0x09; /* wLangId-Low:  English FIXME: use the first entry. */
+  msg[19] = 0x09; /* wLangId-Low:  English FIXME: use the first entry. */
+  msg[20] = 0x04; /* wLangId-High. */
   msg[21] = 0;    /* bMsgIndex. */
   /* bTeoProlog follows: */
   msg[22] = handle->nonnull_nad? ((1 << 4) | 0): 0;