gnupg/scripts/mdate-sh

#!/bin/sh
# Get modification time of a file or directory and pretty-print it.
# Copyright (C) 1995, 1996, 1997, 2003  Free Software Foundation, Inc.
# written by Ulrich Drepper <drepper@gnu.ai.mit.edu>, June 1995
#
# This program is free software; you can redistribute it and/or modify
# it under the terms of the GNU General Public License as published by
# the Free Software Foundation; either version 2, or (at your option)
# any later version.
#
# This program is distributed in the hope that it will be useful,
# but WITHOUT ANY WARRANTY; without even the implied warranty of
# MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE.  See the
# GNU General Public License for more details.
#
# You should have received a copy of the GNU General Public License
# along with this program; if not, write to the Free Software Foundation,
# Inc., 59 Temple Place - Suite 330, Boston, MA 02111-1307, USA.

# As a special exception to the GNU General Public License, if you
# distribute this file as part of a program that contains a
# configuration script generated by Autoconf, you may include it under
# the same distribution terms that you use for the rest of that program.

# Prevent date giving response in another language.
LANG=C
export LANG
LC_ALL=C
export LC_ALL
LC_TIME=C
export LC_TIME

save_arg1="$1"

# Find out how to get the extended ls output of a file or directory.
if ls -L /dev/null 1>/dev/null 2>&1; then
  ls_command='ls -L -l -d'
else
  ls_command='ls -l -d'
fi

# A `ls -l' line looks as follows on OS/2.
#  drwxrwx---        0 Aug 11  2001 foo
# This differs from Unix, which adds ownership information.
#  drwxrwx---   2 root  root      4096 Aug 11  2001 foo
#
# To find the date, we split the line on spaces and iterate on words
# until we find a month.  This cannot work with files whose owner is a
# user named `Jan', or `Feb', etc.  However, it's unlikely that `/'
# will be owned by a user whose name is a month.  So we first look at
# the extended ls output of the root directory to decide how many
# words should be skipped to get the date.

# On HPUX /bin/sh, "set" interprets "-rw-r--r--" as options, so the "x" below.
set - x`$ls_command /`

# Find which argument is the month.
month=
command=
until test $month
do
  shift
  # Add another shift to the command.
  command="$command shift;"
  case $1 in
    Jan) month=January; nummonth=1;;
    Feb) month=February; nummonth=2;;
    Mar) month=March; nummonth=3;;
    Apr) month=April; nummonth=4;;
    May) month=May; nummonth=5;;
    Jun) month=June; nummonth=6;;
    Jul) month=July; nummonth=7;;
    Aug) month=August; nummonth=8;;
    Sep) month=September; nummonth=9;;
    Oct) month=October; nummonth=10;;
    Nov) month=November; nummonth=11;;
    Dec) month=December; nummonth=12;;
  esac
done

# Get the extended ls output of the file or directory.
set - x`eval "$ls_command \"\$save_arg1\""`

# Remove all preceding arguments
eval $command

# Get the month.  Next argument is day, followed by the year or time.
case $1 in
  Jan) month=January; nummonth=1;;
  Feb) month=February; nummonth=2;;
  Mar) month=March; nummonth=3;;
  Apr) month=April; nummonth=4;;
  May) month=May; nummonth=5;;
  Jun) month=June; nummonth=6;;
  Jul) month=July; nummonth=7;;
  Aug) month=August; nummonth=8;;
  Sep) month=September; nummonth=9;;
  Oct) month=October; nummonth=10;;
  Nov) month=November; nummonth=11;;
  Dec) month=December; nummonth=12;;
esac

day=$2

# Here we have to deal with the problem that the ls output gives either
# the time of day or the year.
case $3 in
  *:*) set `date`; eval year=\$$#
       case $2 in
	 Jan) nummonthtod=1;;
	 Feb) nummonthtod=2;;
	 Mar) nummonthtod=3;;
	 Apr) nummonthtod=4;;
	 May) nummonthtod=5;;
	 Jun) nummonthtod=6;;
	 Jul) nummonthtod=7;;
	 Aug) nummonthtod=8;;
	 Sep) nummonthtod=9;;
	 Oct) nummonthtod=10;;
	 Nov) nummonthtod=11;;
	 Dec) nummonthtod=12;;
       esac
       # For the first six month of the year the time notation can also
       # be used for files modified in the last year.
       if (expr $nummonth \> $nummonthtod) > /dev/null;
       then
	 year=`expr $year - 1`
       fi;;
  *) year=$3;;
esac

# The result.
echo $day $month $year