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Update explanation for All-true-ation 

#255
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Chris Milson 2021-02-18 19:05:40 +09:00
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@ -1273,8 +1273,8 @@ Why's this True-False alteration?
```
- `all([])` returns `True` since the iterable is empty.
- `all([[]])` returns `False` because `not []` is `True` is equivalent to `not False` as the list inside the iterable is empty.
- `all([[[]]])` and higher recursive variants are always `True` since `not [[]]`, `not [[[]]]`, and so on are equivalent to `not True`.
- `all([[]])` returns `False` because the passed array has one element, `[]`, and in python, an empty list is falsy.
- `all([[[]]])` and higher recursive variants are always `True`. This is because the passed array's single element (`[[...]]`) is no longer empty, and lists with values are truthy.
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