The out of scope variable, nonlocal, #193
This commit is contained in:
parent
ab7530f7fd
commit
dc7b16c0f3
|
@ -2023,6 +2023,53 @@ UnboundLocalError: local variable 'a' referenced before assignment
|
|||
|
||||
---
|
||||
|
||||
### ▶ The out of scope variable (again?)
|
||||
<!-- Example ID: TODO: WHAT IS THIS? --->
|
||||
```py
|
||||
def some_func():
|
||||
a = 1
|
||||
def some_inner_func():
|
||||
return a
|
||||
return some_inner_func()
|
||||
|
||||
def another_func():
|
||||
a = 1
|
||||
def another_inner_func():
|
||||
a += 1
|
||||
return a
|
||||
return another_inner_func()
|
||||
```
|
||||
|
||||
**Output:**
|
||||
```py
|
||||
>>> some_func()
|
||||
1
|
||||
>>> another_func()
|
||||
UnboundLocalError: local variable 'a' referenced before assignment
|
||||
```
|
||||
|
||||
#### 💡 Explanation:
|
||||
* When you make an assignment to a variable in scope, it becomes local to that scope. So `a` becomes local to the scope of `another_inner_func` inside `another_func`, but it has not been initialized previously in the same scope, which throws an error.
|
||||
* Read [this](http://sebastianraschka.com/Articles/2014_python_scope_and_namespaces.html) short but an awesome guide to learn more about how namespaces and scope resolution works in Python.
|
||||
* To modify the outer scope variable `a` in `another_inner_func`, use the `nonlocal` keyword.
|
||||
```py
|
||||
def another_func():
|
||||
a = 1
|
||||
def another_inner_func():
|
||||
nonlocal a
|
||||
a += 1
|
||||
return a
|
||||
return another_inner_func()
|
||||
```
|
||||
|
||||
**Output:**
|
||||
```py
|
||||
>>> another_func()
|
||||
2
|
||||
```
|
||||
|
||||
---
|
||||
|
||||
### ▶ Deleting a list item while iterating
|
||||
<!-- Example ID: 4cc52d4e-d42b-4e09-b25f-fbf5699b7d4e --->
|
||||
```py
|
||||
|
|
Loading…
Reference in New Issue